Question

If (6y − 11)(6y + 11) = ay2 − b, what is the value of a?

Answer 1

hints:

difference of square rule

(x-y)*(x+y) = x^2 - y^2

(3z+2x)*(3z-2x) = (3z)^2 - (2x)^2 = 9z^2 - 4x^2

(2y+5)*(2y-5) = (4y)^2 - (5)^2 = 16y^2 - 25

none of these are the answer. They're just examples

Answer 2

That didn't really help me :( can I just get the answer?

Answer 3

Difference of squares rule

\[\Large (\color{red}{x} - \color{blue}{y})(\color{red}{x} + \color{blue}{y}) = (\color{red}{x})^2 - (\color{blue}{y})^2\]

\[\Large (\color{red}{6y} - \color{blue}{11})(\color{red}{6y} + \color{blue}{11}) = (\color{red}{6y})^2 - (\color{blue}{11})^2 = ???\]

I'll let you do that last part

Answer 4

Would it be 36y^2- 121?

Answer 5

yes it would be

Answer 6

so a would be 36

Answer 7

correct