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Five times the number of test tubes in a school's chemistry lab exceeds three times the number of beakers it has by 660. The sum of 2 times the number of test tubes and five times the number of beakers is 450. If b is the number of beakers and t is the number of test tubes, what is the system of linear equations representing the situation? How many beakers are in the school lab? How many test tubes are in the school lab?
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do you have any idea how to solve?
No @Deeezzzz
using t= test tubes b= beakers Okay can't we say that 5t=3b+660
and 2t+5b=450
2t+5b=450 5t=3b+660 then we just solve the linear equations and solve for t and b respectively
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