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A system of equations is given below: y = 4x − 3 2x + 7y = 41 Which of the following steps could be used to solve by substitution? 2(y = 4x − 3) + 7y = 41 4x − 3 = 2x + 7y 2x + 7(4x − 3) = 41 2(y = 4x − 3)
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from first equation we have y, since: \[\Large y = 4x - 3\]
now I replace y with 4x-3 into the second equation, so I get: \[\Large 2x + 7\left( {4x - 3} \right) = 41\]
medal me and I will guide you through it
nvm
bye
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