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If f(x)=log3 (x+1), what is f-1(2)
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3log(3)
The answers are 1,8,10,27
You found f(2) @asdfghjkl24562
solve for x \[2=\log_3(x+1)\]
ohhhhhhh
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hint: using the definition of logarithm, we can write: \[\Large x + 1 = {3^y}\]
Oh the logarithmic is the in the inverse of exponential functions, so all you have to do is cinvert it to an exponential function and substitute the velue
You guys are amazing
\[(2)+1=3^{y}\]
thanks!
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3=3\[^{y}\]
\[3 = 3^{y}\]
it's suppose to be \[3^2=x+1\]
no
\[f^{-1}(2) =x \text{ implies } f(x)=2 \\ \text{ so we need to solve } 2=\log_3(x+1) \\ \text{ and converting to exponential form gives } \\ 3^2=x+1\]
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Oh ya
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