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Mathematics 17 Online
OpenStudy (anonymous):

Help with adding square roots

OpenStudy (anonymous):

\[2\sqrt{k}+\sqrt{k}-3\sqrt{k}\]

OpenStudy (idku):

if you had \( \tt 2x+x-3x\) then what would you get?

OpenStudy (anonymous):

just x right?

OpenStudy (anonymous):

-x

OpenStudy (idku):

2 + 1 - 3 = 0

OpenStudy (anonymous):

yeah then 0

OpenStudy (idku):

2x + x - 3x = 0

OpenStudy (idku):

So then, \(\tt 2\sqrt{k}+\sqrt{k}-3\sqrt{k}=0?\)

OpenStudy (idku):

is that correct?

OpenStudy (anonymous):

looks like it idk answer choices are a.) 0 b.) -sqrt k c.) sqrt 3k

OpenStudy (idku):

ok, so we have agreed upon the fact that: \(\tt 2+1-3=0\) And same way, \(\tt 2a+a-3a~~\longrightarrow~~2a+1a-3a=0\) Now, \(\tt 2\sqrt{k}+\sqrt{k}-\sqrt{k}a~~\longrightarrow~~2\sqrt{k}-1\sqrt{k}-3\sqrt{k}=?\)

OpenStudy (anonymous):

0

OpenStudy (idku):

Yes, that is the correct answer.

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