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Mathematics 22 Online
OpenStudy (horsegal244):

I Need Help I Will Give Fan And Medals!

OpenStudy (horsegal244):

A circular picture is 8 inches in diameter. Part A What is the area of the picture in square inches? A. 4π square inches B. 8π square inches C. 16π square inches D. 32π square inches Part B A frame that is 2 inches wide surrounds the picture. What is the total area of the picture and the frame in square inches? A. 4π square inches B. 12π square inches C. 36π square inches D. 40π square inches

OpenStudy (horsegal244):

@hybrik

OpenStudy (anonymous):

\[A = \pi r^2\]

OpenStudy (horsegal244):

ummmmm

OpenStudy (anonymous):

=π·42≈50.26548

OpenStudy (horsegal244):

I don't get it.......

OpenStudy (anonymous):

oh the answer is in pi so 42 pi is your answer

OpenStudy (anonymous):

what don't you get?

OpenStudy (horsegal244):

oh

OpenStudy (horsegal244):

But 42 is not in the answers...

OpenStudy (anonymous):

or 16 pi sry

OpenStudy (welshfella):

Part A = pi r^2 = pi 4^2

OpenStudy (welshfella):

as 4 is the radius

OpenStudy (anonymous):

idk why I wrote 42 xD

OpenStudy (welshfella):

Part B the radius increases by 2 so area = pi * 6^2

OpenStudy (horsegal244):

@Chumpian How did you get that?

OpenStudy (horsegal244):

Part A

OpenStudy (anonymous):

\[A = \pi r^2\] so 4 is the radius (r) and what's 4 squared?

OpenStudy (horsegal244):

16

OpenStudy (anonymous):

yep and they want the answer in terms of pi so 16pi is your answer

OpenStudy (horsegal244):

Now i need part B

OpenStudy (anonymous):

So again you use the equation \[A = \pi r^2\]

OpenStudy (horsegal244):

ok

OpenStudy (anonymous):

They said they added two inches to the frame

OpenStudy (anonymous):

so the radius is now 6

OpenStudy (anonymous):

So what do you do next?

OpenStudy (welshfella):

area = pi r^2 where r = radius r is now 6 so its pi * 6^2 = 36 pi

OpenStudy (anonymous):

Well I was gonna let her do that but thx xD

OpenStudy (welshfella):

oh sorry

OpenStudy (horsegal244):

Ok sry what is going on?

OpenStudy (horsegal244):

@Chumpian

OpenStudy (anonymous):

ok so the radius for part B is 6

OpenStudy (horsegal244):

ok

OpenStudy (anonymous):

We are doing the same thing as we did in part A

OpenStudy (horsegal244):

ok

OpenStudy (anonymous):

so what do we do with the radius that equals 6

OpenStudy (horsegal244):

idrk

OpenStudy (anonymous):

\[A = \pi r^2\]

OpenStudy (horsegal244):

Ok but that is A

OpenStudy (anonymous):

but we are doing the same thing as Part A but just with a larger radius

OpenStudy (horsegal244):

Ok

OpenStudy (anonymous):

So when we plug in the 6 \[A = \pi 6^2\]

OpenStudy (anonymous):

What do you do with the 6?

OpenStudy (horsegal244):

multiply is by itself so 12

OpenStudy (anonymous):

that would be 6 x 2 = 12 but squaring a number would be 6 x 6 = 36

OpenStudy (horsegal244):

Oh yea sorry

OpenStudy (horsegal244):

so then 36?

OpenStudy (anonymous):

yep and they want it in terms of pi So your answer is?

OpenStudy (horsegal244):

36π

OpenStudy (anonymous):

yep :)

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