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OpenStudy (horsegal244):
A circular picture is 8 inches in diameter.
Part A
What is the area of the picture in square inches?
A. 4π square inches
B. 8π square inches
C. 16π square inches
D. 32π square inches
Part B
A frame that is 2 inches wide surrounds the picture. What is the total area of the picture and the frame in square inches?
A. 4π square inches
B. 12π square inches
C. 36π square inches
D. 40π square inches
OpenStudy (horsegal244):
@hybrik
OpenStudy (anonymous):
\[A = \pi r^2\]
OpenStudy (horsegal244):
ummmmm
OpenStudy (anonymous):
=π·42≈50.26548
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OpenStudy (horsegal244):
I don't get it.......
OpenStudy (anonymous):
oh the answer is in pi so 42 pi is your answer
OpenStudy (anonymous):
what don't you get?
OpenStudy (horsegal244):
oh
OpenStudy (horsegal244):
But 42 is not in the answers...
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OpenStudy (anonymous):
or 16 pi sry
OpenStudy (welshfella):
Part A = pi r^2 = pi 4^2
OpenStudy (welshfella):
as 4 is the radius
OpenStudy (anonymous):
idk why I wrote 42 xD
OpenStudy (welshfella):
Part B
the radius increases by 2
so area = pi * 6^2
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OpenStudy (horsegal244):
@Chumpian How did you get that?
OpenStudy (horsegal244):
Part A
OpenStudy (anonymous):
\[A = \pi r^2\] so 4 is the radius (r) and what's 4 squared?
OpenStudy (horsegal244):
16
OpenStudy (anonymous):
yep and they want the answer in terms of pi so 16pi is your answer
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OpenStudy (horsegal244):
Now i need part B
OpenStudy (anonymous):
So again you use the equation \[A = \pi r^2\]
OpenStudy (horsegal244):
ok
OpenStudy (anonymous):
They said they added two inches to the frame
OpenStudy (anonymous):
so the radius is now 6
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OpenStudy (anonymous):
So what do you do next?
OpenStudy (welshfella):
area = pi r^2 where r = radius
r is now 6
so its pi * 6^2 = 36 pi
OpenStudy (anonymous):
Well I was gonna let her do that but thx xD
OpenStudy (welshfella):
oh sorry
OpenStudy (horsegal244):
Ok sry what is going on?
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OpenStudy (horsegal244):
@Chumpian
OpenStudy (anonymous):
ok so the radius for part B is 6
OpenStudy (horsegal244):
ok
OpenStudy (anonymous):
We are doing the same thing as we did in part A
OpenStudy (horsegal244):
ok
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OpenStudy (anonymous):
so what do we do with the radius that equals 6
OpenStudy (horsegal244):
idrk
OpenStudy (anonymous):
\[A = \pi r^2\]
OpenStudy (horsegal244):
Ok but that is A
OpenStudy (anonymous):
but we are doing the same thing as Part A but just with a larger radius
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OpenStudy (horsegal244):
Ok
OpenStudy (anonymous):
So when we plug in the 6 \[A = \pi 6^2\]
OpenStudy (anonymous):
What do you do with the 6?
OpenStudy (horsegal244):
multiply is by itself
so 12
OpenStudy (anonymous):
that would be 6 x 2 = 12 but squaring a number would be 6 x 6 = 36
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OpenStudy (horsegal244):
Oh yea sorry
OpenStudy (horsegal244):
so then 36?
OpenStudy (anonymous):
yep and they want it in terms of pi So your answer is?