Please help!!! Solve -np - 90 > 30 for n. Show your work.
for n... so we need n by itself...
ok
alright... so we need to add what number to both sides so we have all numbers to the right
-np -90 > 30 I want all numbers to the right.. .
so how do we cancel out the 90 in the left? and have 90 on the right?
+90
yup add 90 to both sides -np>30+90 and what's 30+90?
120
yup so now we have -np>120 we just need to divide when dividing both sides with a negative sign we need to switch the inequality signs
now we need just an n by itself... what can we divide to both sides to make that happen?
divide by p
yes we divide by p , but remember we want just positive n by itself so we need to divide both sides by -p and since we have a negative sign involved, the inequality sign gets switched.
oh ok
-np >120 \[n < \frac{120}{-p}\]
though negative signs in the denominator is frowned upon :( so just place it in the numerator/ \[n < \frac{-120}{p}\]
ok
so now we have n by itself... we're done . :)
thank you :)
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