Question

Find the first six terms of the sequence.

a1 = -3, an = 2 ● an-1

Answer 1

replace n with 2

Answer 2

\[a_1=-3 \\ a_n=2 \cdot a_{n-1} \\ \text{ replacing } n \text{ with } 2 \\ a_2=2 \cdot a_{2-1} \\ a_2=2 \cdot a_1 \text {since 2-1=1} \\ \text{ now recall } a_1=-3 \\ \text{ replace } a_1 \text{ with -3 } \\ a_2=2 (-3)=-6 \text{, -6 is the second term }\]

Answer 3

try finding the 3rd term by replacing n with 3 instead of 2

Answer 4

-12 3
-24 4
-48 5
-96 6

Answer 5

checking...
\[a_3=2 \cdot a_{3-1} \\ a_3=2 \cdot a_2 \\ \text{ but remember } a_2=-6 \\ a_3=2(-6)=-12\]
your third term is right
anyways we are just multiplying previous term by 2
so we started with -3
-3(2)=-6
-6(2)=-12
-12(2)=-24
-24(2)=-48
-48(2)=-96
yep seems great

Answer 6

thanks

Answer 7

I might have a few more questions later

Answer 8

hey on the previous question where you asked what 9+10
like was that really the question?

Answer 9

lol, no @myininaya

Answer 10

Like if you can give me the actual question I might be able to help you with it

Answer 11

lol

Answer 12

Im just studying for my semester exam so it can be any type of question. I dont have any right now tho

Answer 13

oh ok

Answer 14

actually I lied, I'll post a new question