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OpenStudy (anonymous):
Find the standard form of the equation of the parabola with a focus at (0, 6) and a directrix at y = -6.
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OpenStudy (anonymous):
@myininaya
myininaya (myininaya):
Hey.
myininaya (myininaya):
so I like to a do a rough drawing to first figure out if my p is going to be negative or positive and where my vertex is going to be.
OpenStudy (anonymous):
it should be positive, just making a mental sketch
myininaya (myininaya):
p is negative if the directrix is above the focus.
p is positive if the directrix is below the focus.
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myininaya (myininaya):
The vertex is halfway between the vertex and the directrix.
OpenStudy (anonymous):
0,0
myininaya (myininaya):
right
myininaya (myininaya):
and also right on the first thing
myininaya (myininaya):
so we just need to figure out what p is
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myininaya (myininaya):
p is the distance between the focus and the vertex
myininaya (myininaya):
or you can look at it as the distance between the vertex and the directrix
OpenStudy (anonymous):
so 6
myininaya (myininaya):
\[4py=x^2 \]
is what we had
and we knew p was going to be postive because focus was above directrix
and yep just replace p with 6
OpenStudy (anonymous):
so 24y=x²
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myininaya (myininaya):
yep
or you can write it as
y=x^2/24
I just divided 24 on both sides
OpenStudy (anonymous):
my answer is y = 1/24x²
myininaya (myininaya):
that sounds good too
OpenStudy (anonymous):
yes, My answer choice is written in the form I wrote it in
OpenStudy (anonymous):
thanks
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