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Mathematics 15 Online
OpenStudy (anonymous):

WILL MEDAL AND FAN NO LIE Cards numbered 1, 1, 2, 3, 4, 4, 4, 5, 6, 6, 7, 8, 8, 8, and 9 are placed in a bag. If a card is drawn from the bag and then replaced 135 times, about how many times would a 6 be drawn? A. 2 B. 9 C. 15 D. 18

Vocaloid (vocaloid):

(number of 6's/total number of cards)*135

OpenStudy (anonymous):

im confused

Vocaloid (vocaloid):

how many cards have 6 on them?

OpenStudy (welshfella):

there are 2 cards marked 6 out of a total of 15 cards so probability of picking a 6 in one draw is = ?

OpenStudy (anonymous):

2 @Vocaloid

Vocaloid (vocaloid):

right, and how many total cards are there?

OpenStudy (anonymous):

@welshfella

OpenStudy (welshfella):

I mentioned that above

OpenStudy (anonymous):

IS IT C

OpenStudy (anonymous):

@welshfella

Vocaloid (vocaloid):

the answer isn't c, would you mind telling me how many total cards there are?

OpenStudy (anonymous):

wait i think its D srry

jimthompson5910 (jim_thompson5910):

As Vocaloid wrote \[\Large \text{Expected Number of 6's} = \frac{\text{Number of 6's}}{\text{Total number of cards}}*135\] \[\Large \text{Expected Number of 6's} = \frac{2}{15}*135\] \[\Large \text{Expected Number of 6's} = ???\]

OpenStudy (anonymous):

sooo just do 2/15 x 135 :/

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

18 soooo D

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

yep 18

OpenStudy (anonymous):

ok can u help me with more @jim_thompson5910

OpenStudy (anonymous):

@automaticloveletter

OpenStudy (anonymous):

@taramgrant0543664

OpenStudy (anonymous):

HELP PLZZZZ

OpenStudy (taramgrant0543664):

Is there a new question?

OpenStudy (anonymous):

yea i need help with math

OpenStudy (taramgrant0543664):

Well you can ask them and just tag me in them I'm happy to help

OpenStudy (anonymous):

ok

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