WILL MEDAL AND FAN NO LIE
Cards numbered 1, 1, 2, 3, 4, 4, 4, 5, 6, 6, 7, 8, 8, 8, and 9 are placed in a bag.
If a card is drawn from the bag and then replaced 135 times, about how many times would a 6 be drawn?
A.
2
B.
9
C.
15
D.
18
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Vocaloid (vocaloid):
(number of 6's/total number of cards)*135
OpenStudy (anonymous):
im confused
Vocaloid (vocaloid):
how many cards have 6 on them?
OpenStudy (welshfella):
there are 2 cards marked 6 out of a total of 15 cards
so probability of picking a 6 in one draw is = ?
OpenStudy (anonymous):
2 @Vocaloid
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Vocaloid (vocaloid):
right, and how many total cards are there?
OpenStudy (anonymous):
@welshfella
OpenStudy (welshfella):
I mentioned that above
OpenStudy (anonymous):
IS IT C
OpenStudy (anonymous):
@welshfella
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Vocaloid (vocaloid):
the answer isn't c, would you mind telling me how many total cards there are?
OpenStudy (anonymous):
wait i think its D srry
jimthompson5910 (jim_thompson5910):
As Vocaloid wrote
\[\Large \text{Expected Number of 6's} = \frac{\text{Number of 6's}}{\text{Total number of cards}}*135\]
\[\Large \text{Expected Number of 6's} = \frac{2}{15}*135\]
\[\Large \text{Expected Number of 6's} = ???\]
OpenStudy (anonymous):
sooo just do 2/15 x 135 :/
jimthompson5910 (jim_thompson5910):
yes
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
18 soooo D
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
yep 18
OpenStudy (anonymous):
ok can u help me with more @jim_thompson5910
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OpenStudy (anonymous):
@automaticloveletter
OpenStudy (anonymous):
@taramgrant0543664
OpenStudy (anonymous):
HELP PLZZZZ
OpenStudy (taramgrant0543664):
Is there a new question?
OpenStudy (anonymous):
yea i need help with math
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OpenStudy (taramgrant0543664):
Well you can ask them and just tag me in them I'm happy to help