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If p(x) = 2x2 – 4x and q(x) = x – 3, what is (p ºq)(x)
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\[p(x)=2x^2-4x,q(x)=x-3\] and you want \[p\circ q(x)\] right?
yes
@satellite73
SOLOMON MY BOY :))
(pº q)(x) is same as p(q(x)). you take the function q(x), and plug it instead of x into the f(x).
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p(x) = 2x² – 4x and q(x) = x – 3 p(q(x)) = 2(q(x))²-4(q(x)) p(q(x)) = 2(x-3)²-4(x-3)
then simplify
2x2−16x+30?
yes, correct!
yes ty !!
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yw
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