Question

Using the quadratic formula to solve 2x2 = 4x – 7, what are the values of x?

Answer 1

rewrite the equation to get
2x^2-4x+7=0
where a=2 , b=-4 and c=7
now substitute the values in the quadratic formula \[\frac{ -b \pm \sqrt{(b ^{2}-4ac)} }{ 2a }\]

Answer 2

\[\frac{ -(-4)\pm \sqrt{((-4)^{2}-4(2)(7))} }{ 2(2) }\]now simplify...

Answer 3

its been a while since ive done this and ive lost it

Answer 4

Linda I need you for a minute

Answer 5

continuing the step:
\[\frac{ (4)\pm \sqrt{(16)-(56)} }{ 4 }\]

Answer 6

\[\frac{ (4)\pm \sqrt{(-40)} }{ (4) }=\frac{ (4)\pm \sqrt{(40)(-1)} }{ 4 }\]

Answer 7

complex numbers:
\[\frac{ (4)\pm(\sqrt{40})(\sqrt{-1}) }{ 4 }=\frac{ (4)\pm(\sqrt{40})i }{ 4 }\]
:)