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OpenStudy (lalaland_lauren):
@satellite73
OpenStudy (lalaland_lauren):
@vmac2122
OpenStudy (misty1212):
HI!!
OpenStudy (lalaland_lauren):
Hello :)
OpenStudy (misty1212):
we can multiply each one out and see what works, or perhaps we can work smarter
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OpenStudy (misty1212):
you see how the last term is \(2y\) right?
OpenStudy (lalaland_lauren):
That's my problem, I get so confused multiplying everything out :( and yeah
OpenStudy (misty1212):
that gets rid if b and d
do you see why?
OpenStudy (lalaland_lauren):
Yeah, that's actually a really cool loophole
OpenStudy (misty1212):
\[ (5x + y)(2x + 3)\] last term will be \(3y\) so that is no good
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OpenStudy (misty1212):
same here \[ (5x + 3)(2x + y)\]
OpenStudy (lalaland_lauren):
I figured it out, it's A
OpenStudy (misty1212):
so we can try the first one \[ (3x + 2)(5x + y)\]
OpenStudy (misty1212):
yeah that looks good
OpenStudy (lalaland_lauren):
Yayyyyy I got it! :)
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OpenStudy (misty1212):
\[\huge \color\magenta\heartsuit\]
OpenStudy (lalaland_lauren):
Thank youuuu!
OpenStudy (misty1212):
you are quite welcome
got more?
OpenStudy (lalaland_lauren):
A few, yes hold on
OpenStudy (misty1212):
kk
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OpenStudy (lalaland_lauren):
Graph of a cubic polynomial that falls to the left and rises to the right with graph touching x axis at negative 1 and x intercept at 1
Which of the following functions best represents the graph?
f(x) = x3 + x2 − 4x − 4
f(x) = x3 + x2 − x − 1
f(x) = x3 + 3x2 − 4x − 12
f(x) = x3 + 2x2 − 2x − 1
OpenStudy (lalaland_lauren):
OpenStudy (misty1212):
ok we can do this
OpenStudy (misty1212):
you see how it only touches where \(x=-1\)?
OpenStudy (lalaland_lauren):
Yeah, and where x=1
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OpenStudy (misty1212):
actually there is a difference,
where \(x=1\) it CROSSES the axis, at \(x=-1\) it comes up, touches it, but does not cross, goes back down
OpenStudy (misty1212):
so it has to zeros, one at \(x=-1\) and one at \(x=1\)
because it crosses at \(x=1\) one factor is \((x-1)\)
OpenStudy (misty1212):
because it touches at \(x=-1\) then the factor looks like \((x+1)^2\)
OpenStudy (misty1212):
lol "has two zeros" i meant
OpenStudy (misty1212):
final job is to multiply
\[(x+1)^2(x-1)\] to see what we get
i would cheat!!
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OpenStudy (lalaland_lauren):
I love that whole band, actually!
OpenStudy (misty1212):
lol thought so !!
OpenStudy (lalaland_lauren):
How'd you know? XD
OpenStudy (misty1212):
american psychic
OpenStudy (lalaland_lauren):
*clapping emoji*
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OpenStudy (misty1212):
\[\color\red\heartsuit\]
OpenStudy (lalaland_lauren):
Unfortunately I have to go to bed now :( I'm extremely tired and I'm pretty sure I have to get up early to keep working on assignments. Will you be on in the morning?
OpenStudy (misty1212):
i can be here at about 9 or 9:30
earlier probably not
OpenStudy (misty1212):
tag me if you like, i will try to help if i can!
OpenStudy (misty1212):
my bed time too
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OpenStudy (lalaland_lauren):
That's a good time for me :) alrighty, thanks so much for helping me! good night c: