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hey since its the same wire the resistivities in both instances are the same so get 2 equations for resistivity equalize them and get the value for resistance . I got it as * ohms
\[\rho = \frac{ RA }{ L }\]
\[\frac{ 2A }{ L } = \frac{ RA }{ 4L }\]
=2Ω*(2)*(2) =8Ω
thank you! and is thats the correct answer and did I show the work correctly?
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yeah !
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