10√x5•x4•x2 simply
@OregonDuck
those are powers right
yes
\[10\sqrt{x^5}* x^4 *x^2\]
is the 5 under the root or outside
yes
remember \[\sqrt{x} = x ^{1/2}\]
also remember, a power raised to a power, you multiply them together... \[[x^{a}]^b = x^{a*b}\]
and lastly, remember, multiplying a base raised to two powers, you ADD them \[x^a * x^b = x^{a+b}\]
so, with those notes, can you start it
i got x = 5
you cant solve for x, it is not an equation, just make it look different, simpler
x^ 10/11
...ill show you step by step
For the first root term \[10\sqrt{x^5} = 10[x ^{5}]^{1/2} = 10x^{5*1/2} = 10x^{5/2}\]
Then when multiplying that by x^4 and x^2 you add the exponents \[10x^{5/2}*x^4*x^2 = 10x^{5/2+4+2}\]
so i got \[10x^{17/2}\]
you just have to remember the three or so basic exponent rules, then you can do all the probs
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