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Mathematics 12 Online
OpenStudy (anonymous):

Yet another proof..

OpenStudy (anonymous):

about?

OpenStudy (anonymous):

Okay please post the question.

OpenStudy (anonymous):

OpenStudy (anonymous):

he can help you here

OpenStudy (anonymous):

I'm trying to post the options hold on haha @alexistheking777

OpenStudy (anonymous):

OpenStudy (anonymous):

I don't know what he talking bout lol I don't do well in Geometry. But lemme get some people for ya. @ganeshie8 @pooja195

OpenStudy (arindameducationusc):

I got it..

OpenStudy (arindameducationusc):

It should be C.... because.....

OpenStudy (anonymous):

@arindameducationusc U r a genius

OpenStudy (arindameducationusc):

KJ, JL, and then comes angle JLK. So, Option C again....

OpenStudy (arindameducationusc):

Thank you @alexistheking777

OpenStudy (arindameducationusc):

anybody can argue.....

OpenStudy (anonymous):

Thank you @arindameducationusc this is the proof section so I am completely lost. I have so many questions

OpenStudy (anonymous):

i agree

OpenStudy (anonymous):

Since L is the midpoint of the line, ∠JLK = ∠NLM. cos(JLK) must be equal to cos(NLM).

OpenStudy (arindameducationusc):

My pleasure @jillina29 just keep asking.... :)

OpenStudy (anonymous):

So yup C

OpenStudy (anonymous):

The next one is even harder.. @arindameducationusc

OpenStudy (arindameducationusc):

please post, will definitely try my best

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