Mathematics
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OpenStudy (anonymous):
Yet another proof..
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OpenStudy (anonymous):
about?
OpenStudy (anonymous):
Okay please post the question.
OpenStudy (anonymous):
OpenStudy (anonymous):
he can help you here
OpenStudy (anonymous):
I'm trying to post the options hold on haha @alexistheking777
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OpenStudy (anonymous):
OpenStudy (anonymous):
I don't know what he talking bout lol I don't do well in Geometry. But lemme get some people for ya. @ganeshie8 @pooja195
OpenStudy (arindameducationusc):
I got it..
OpenStudy (arindameducationusc):
It should be C.... because.....
OpenStudy (anonymous):
@arindameducationusc U r a genius
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OpenStudy (arindameducationusc):
KJ, JL, and then comes angle JLK. So, Option C again....
OpenStudy (arindameducationusc):
Thank you @alexistheking777
OpenStudy (arindameducationusc):
anybody can argue.....
OpenStudy (anonymous):
Thank you @arindameducationusc this is the proof section so I am completely lost. I have so many questions
OpenStudy (anonymous):
i agree
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OpenStudy (anonymous):
Since L is the midpoint of the line, ∠JLK = ∠NLM.
cos(JLK) must be equal to cos(NLM).
OpenStudy (arindameducationusc):
My pleasure @jillina29 just keep asking.... :)
OpenStudy (anonymous):
So yup C
OpenStudy (anonymous):
The next one is even harder.. @arindameducationusc
OpenStudy (arindameducationusc):
please post, will definitely try my best