Question

what are the equations to these diagrams? (attachment) please help will medal!!

Answer 1

PLEASE HELP!

Answer 2

the first one is a quadratic equation with a negative coefficient of x^2. It has zeros of 2 and -8.
and a vertex at (-3,6)

can you find the equation from this info?

Answer 3

For the 1st diagram
\[-(x+3)^2=4(y-6)\]

Answer 4

is this right? −(x+3)2=4(y−6) @welshfella

Answer 5

the ellipse equation is
\[\frac{ (y-4)^2 }{ 6^2 }+\frac{ (x-3)^2 }{ 4^2 }=1\]

Answer 6

for the first one? @saseal

Answer 7

yes the first picture

Answer 8

what about the second? @saseal

Answer 9

yes that is correct for the first graph

Answer 10

im doing the circle now, its
\[(x+6)^2+(y+2)^2=5^2\]

Answer 11

what about #13 and #14? then i will figure out the rest myself thank you for all ur help @saseal

Answer 12

\[\frac{ (x-7)^2 }{ 2^2 }-\frac{ y-2)^2 }{ 2^2}=1\]
for the hyperbola

Answer 13

circle is #13 and hyperbola is #14

Answer 14

what about the one on the top right?

Answer 15

the oval @saseal

Answer 16

2nd picture?

Answer 17

yes

Answer 18

gimme a few minutes

Answer 19

thank you so much

Answer 20

First oval is
\[\frac{ (x-7)^2 }{ 6^2 }+\frac{ y^2 }{ 3^2 }=1\]

Answer 21

if i tag you in some other ones on a different question could you help?

Answer 22

plz dont just give answers saseal Code of Conduct asks us to Guide the user to the answers

Answer 23

okies

Answer 24

so I can't give ya answer now, work the last one out yourself; parabola equation for that curve looks something like this :)
\[(y+1)^2=4p(x-4)^2\]