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Mathematics 13 Online
OpenStudy (anonymous):

Event A: stops on red Event B: stops on yellow Find P(A or B).

OpenStudy (anonymous):

@heretohelpalways

OpenStudy (anonymous):

I am here again

OpenStudy (anonymous):

lol is it 1/2

OpenStudy (anonymous):

Count how many pieces of the circle there are

OpenStudy (anonymous):

12

OpenStudy (anonymous):

there are 12

OpenStudy (anonymous):

how many red are there?

OpenStudy (anonymous):

3

OpenStudy (anonymous):

so 3/12

OpenStudy (anonymous):

and simplify that

OpenStudy (anonymous):

to 1/4

OpenStudy (anonymous):

so 1/4 for the first one, red

OpenStudy (anonymous):

nonono then it lands on yellow so 6/12 and then 1/2

OpenStudy (anonymous):

right?

OpenStudy (anonymous):

is it asking for the probability of it landing on either?

OpenStudy (anonymous):

no both if you look at it first red than yello so 3/12 + 3/12 so 6/12 = 1/2

OpenStudy (anonymous):

I am not sure what it is asking

OpenStudy (zarkon):

1/2 is correct

OpenStudy (anonymous):

because it is 3/12 if it lands on red, and 3/12 if it lands on yellow, so I guess 1/2 would be correct

OpenStudy (zarkon):

A and B are mutually exclusive so P(A or B)=P(A)+P(B)

OpenStudy (anonymous):

:) thanks

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