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Solve x^2 - 2x - 4 = 0
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a. \[1\pm \sqrt{3}\] b. \[{-2,2}\] c. \[1\pm \sqrt{5}\]
you can either complete the square and then solve or use the general quadratic formula... the equation doesn't factor
I'd rather complete the square first so I think I would start by adding four to both sides and then adding one to both sides but I'm not sure about that
Never mind I was able to figure out it was c thanks for the help anyway though.
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