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Solve for x: −3x + 3 < 6
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the equation is just \[\large -3x+3 <6 \] right ?
yes
ok solving an inequality is the same process as solving a regular equation. The only difference is that if we are dividing by a negative number, then the inequality sign switches.
so first subtract 3 on both sides
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okay i got 3 subracting it from 6. crossed out 3 - 3
\[\large -3x+3 <6 \] \[\large -3x+3-3 <6-3\] \[\large -3x <3\] ok good so far now divide by -3 on both sides and since we have a negative number, switch the inequality signs
i got 1 and -1
so it would be x > -1 ?
\[\large -3x <3 \] \[\large \frac{-3}{-3}x <\frac{3}{-3}\] \[\large x >-1\] yes
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