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Mathematics 13 Online
OpenStudy (anonymous):

the explicit formula a[n]=a[1]+(n-1)*d to find the 500th term of the sequence below 24,31,38,45,52

OpenStudy (anonymous):

you need a couple numbers first what is \(a_1\)?

OpenStudy (anonymous):

i think a[1] is the first term which is 24 or it's the common difference which is 7

OpenStudy (anonymous):

yes and yes

OpenStudy (anonymous):

so \(a_1=24, d=7, n=500\) plug them in to \[a_1+(n-1)\times d\]for your answer

OpenStudy (anonymous):

so it would be 24+(500-1)*7 and that give me a value of 3517

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