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Part A: y ≤ 2x − 1 y ≥ − 3x + 2 In the overlapping shaded areas only contain A and E. Graph: http://prntscr.com/45qusv Part B You know A is (2,-3) And E is (3,1) Plug each point into both inequalities to show that they are true. Should have a total of 4 And for C, plot y<-x-1 on the graph. And shade that region. Schools in the shaded region would be the schools he could attend to
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red and blue, in order
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I already did all of them
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