Where is the y-intercept for the line 3x + 2y + 8 = 0
A 2,0
B 0,8
C 0, -4
D -4, 0

Question

Where is the y-intercept for the line 3x + 2y + 8 = 0
A 2,0
B 0,8
C 0, -4
D -4, 0

vocaloid · Answer

when x = 0, what does y = ?

anonymous · Answer

Turn the equation into the y-intercept form. y-intercept form 

 y = mx +b 

m = slope 
b = y-intercept

 
$ \huge 3x + 2y + 8 = 0 $

$ \huge 3x + 8 -8 = -8 $ 

$ \huge 3x + 2y = -8 $

$ \huge 3x - 3x + 2y = -3x - 8 $

$ \huge 2y = -3x -8 $

$ \huge \frac{2y}{ 2} = \frac{-3x}{2}  -\frac{8}{ 2} $

$ \huge y = -\frac{3x}{2} - 4 $



Now this is in y-intercept form y = mx + b. b is your y value to the y-intercept form. Remember y-intercept = the point (0, y) so what is the y intercept point. You can also find the y-intercept by input 0 into the equation like @Vocaloid stated.  suggested.