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Write the equation of a hyperbola with vertices (-5, 0) and (5, 0) and co-vertices at (0, -6) and (0, 6)?
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|dw:1438211364085:dw| get the "a" and "b" components firstly then plug them in keep in mind that, the vertices are at 5,0 and -5,0, so it opens horizontally, meaning the fraction with the "x" variable has the "a" component, that is \(\bf \cfrac{(x-{\color{brown}{ h}})^2}{{\color{purple}{ a}}^2}-\cfrac{(y-{\color{blue}{ k}})^2}{{\color{purple}{ b}}^2}=1 \qquad center\ ({\color{brown}{ h}},{\color{blue}{ k}})\qquad vertices\ ({\color{brown}{ h}}\pm a, {\color{blue}{ k}})\)
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