Question

Add the following equation is posted below.

Answer 1

\[\frac{ 3x-2 }{ x+ 1 } + \frac{ x^2 + x - 2 }{ x^ - 1 }\]

Answer 2

okay so first find a common denominator , do you know how to do that?

Answer 3

\[\frac{ (x-1)(3x-2)+(x+1)(x ^{2}+x-2) }{ (x+1)(x-1) }\]

Answer 4

\[x^2+x-2=x^2+2x-x-2=x \left( x+2 \right)-1\left( x+2 \right)=\left( x+2 \right)\left( x-1 \right)\]

Answer 5

\[\frac{ (x-1)(3x-2)+(x+2)(x-1)(x+1) }{ (x-1)(x+1) }\]

Answer 6

\[\frac{ (x-1)(3x-2+(x+2)(x+1)) }{ (x-1)(x+1) }\]

Answer 7

\[\frac{ (x-1)(x ^{2}+6x) }{ (x-1)(x+1) }\]

Answer 8

\[\frac{ x(x-1)(x+6) }{ (x-1)(x+1) }\]

Answer 9

do u see the the (x-1) can be cancel out?

Answer 10

so what do we have left??

Answer 11

Not sure

Answer 12

\[\frac{ x(x+6) }{ (x+1) }\]