Question

I need help guys with the elimination method for
4y+2x=18
3x+6y=26

Answer 1

\(\bf \begin{array}{llll}
4y+2x=18\\
3x+6y=26
\end{array}\implies
\begin{array}{llll}
2x+4y=18\\
3x+6y=26
\end{array}\impliedby \textit{arranging the variables}
\\ \quad \\
\begin{array}{llll}
2x+4y=18&{\color{brown}{ \times 3}}\\
3x+6y=26&{\color{brown}{ \times -2}}
\end{array}\)


if you multiply those expressions, by THAT MUCH, what do they become?

Answer 2

that is, you mutiply the top by 3
and the bottom one by -2

Answer 3

what if I add both equations down like..
2x+4y=18
+3x+6y=26
equals
5x+10y=44? is this a right step?

Answer 4

Is this an option?