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Geometry 18 Online
OpenStudy (anonymous):

Find the length of the missing side of the triangle below. https://static.k12.com/eli/bb/259/4_25245/2_17293_3_25248/8b7911af6ff4046b03fa260fbecdad8100849773/media/e820732dc346f40000f5bacf183f7cb97174b7c1/mediaasset_774323_1.gif 116 117 188 119

OpenStudy (anonymous):

What do you think? You can use Sine Law to solve this since this is a SAA triangle

OpenStudy (anonymous):

You can solve using \( \huge \frac{\sin 56}{100} = \frac{\sin 76}{x} \)

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

YW. I assume you got it?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

Good Job!!!!

OpenStudy (anonymous):

I will finish it out just for fun :-) You can solve using \( \huge \frac{\sin 56}{100} = \frac{\sin 76}{x} \) \( \huge 100 * \frac{\sin 56}{100} = \frac{ \sin 76}{x} * 100\) \( \huge \sin 56 = \frac{100sin 76}{x} \) \( \huge x* \sin 56 = \frac{100\sin 76}{x} * x\) \( \huge x* \sin 56 = 100\sin 76\) \( \huge x\sin 56 = 100\sin 76\) \( \huge \frac{x\sin 56}{\sin 56} = \frac{100\sin 76}{\sin56}\) \( \huge x = \frac{100\sin 76}{\sin56}\) \( \huge x = 117\)

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