Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

CHECK ATTACHMENT PLEASE

OpenStudy (anonymous):

OpenStudy (mathstudent55):

Let's write our 2 original equations. \(x + 3y = 5\) Eq. 1 \(7x - 8y = 6\) Eq. 2

OpenStudy (mathstudent55):

The problem is asking for a new system of equations which is obtained by keeping equation 2 unchanged, and equation 1 is replaced by the sum of equation 1 and a multiple of equation 2. The new system of equations will be: \(x + 3y = 5\) Eq. 1 kept unchanged \(\_\_\_\_\_\_\_\_\_\_\) A new equation replacing Eq. 2

OpenStudy (mathstudent55):

Now we need to read in the problem what the new equation that replaces equation 2 is. "If equation 2 is multiplied by 1, ..." We are told that equation 2 is multiplied by 1. We already were told that we needed to add a multiple of equation 2 to equation 1. Now we know that the multiple of equation 2 is obtained by multiplying equation 2 by 1. What is equation 2 (below) multiplied by 1 on both sides? \(7x - 8y = 6\) Eq. 2

OpenStudy (anonymous):

can you try it out? :) we can't do it for u

OpenStudy (mathstudent55):

@dom4958 Are you there?

OpenStudy (anonymous):

@mathstudent55 yes

OpenStudy (anonymous):

@dom4958 then try it out

OpenStudy (anonymous):

well if I'm multiplying equation 2 by 1 it would still be the same wouldn't it? or would the - sign change next to 8y?

OpenStudy (mathstudent55):

Ok. What is any number multiplied by 1? What is 2 * 1 = 3 * 1 = pi * 1 = What does multiplying by 1 do to a number?

OpenStudy (anonymous):

@mathstudent55 nothing. it stays the same

OpenStudy (mathstudent55):

Exactly. Multiplying by 1 does not change a number, so multiplying a whole equation by 1 does not change the equation.

OpenStudy (mathstudent55):

That means when we multiply the second equation by 1, we end up with the second equation, just as it was originally.

OpenStudy (mathstudent55):

\(7x - 8y = 6\) Eq. 2 multiplied by 1

OpenStudy (mathstudent55):

Now we add Eq. 1 to Eq. 2 multiplied by 1: \(~~~~~~~~x + 3y = 5\) Eq. 1 \(+~~~7x - 8y = 6\) Eq. 2 multiplied by 1 \(\_\_\_\_\_\_\_\_\_\_\_\_\_\_\)

OpenStudy (mathstudent55):

Do you know how to add the equations in the response above?

OpenStudy (mathstudent55):

Add like terms that are placed one above the other. What is x + 7x = ?

OpenStudy (anonymous):

i think he's afk just waiting for the answer

OpenStudy (anonymous):

sorry I'm back, give me a moment to read what you just said

OpenStudy (anonymous):

would this be correct or am i off track? x+3y=5 + 7x−8y=6 ______________ 8x - 5y =11???

OpenStudy (mathstudent55):

Correct.

OpenStudy (mathstudent55):

Now you replace equation 1 by this new equation, and equation 2 remains the same as it was. What is the new system of equations?

OpenStudy (anonymous):

8x - 5y =11 Eq.1 7x−8y=6 Eq.2

OpenStudy (mathstudent55):

Original system New system \(x+3y=5\) Eq. 1 ---replaced by---> \(8x - 5y = 11\) \(7x−8y=6\) Eq. 2 ---remains as----> \(7x - 8y = 6\)

OpenStudy (mathstudent55):

Exactly. Now read the choices and choose the correct one.

OpenStudy (anonymous):

B thank you so much. you made it really clear i appreciate it

OpenStudy (mathstudent55):

Great. You're welcome. Notice that you did all the work. I just guided you through it. When you have a problem like this one, break down the instructions into small steps and do one step at a time until you get it all done. Good job!

OpenStudy (anonymous):

@mathstudent55 thanks, i honestly have no idea how people can memorize this. I'm good at every other subject but math just gets me lol

OpenStudy (mathstudent55):

Each of us has our strong and weak subjects. This way we can help each other.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!