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f(x) = x^2 + 3; g(x) = Square root of x-2 Find f(g(x)). please help
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\[f(x)=x^2+3\] \[g(x)=\sqrt{x-2}\] plug in g(x) in f(x) \[f(g(x))=fog(x)=(g(x))^2+3\]
put the value of g(x) in the equation and simplify
thank you Nishant_Garg for helping me :)
(g(x))2+3 = (\[\sqrt{x-2}\](x))2+3)
you have to square g(x) and add 3 to it according to f(x)
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\[(g(x))^2=(\sqrt{x-2})^2\]
\[(\sqrt{x-2})^{2}\]
yep! and add 3 to that
\[(\sqrt{x-2)}^{2}+3\]
x+1?
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yep
thank you!
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