Question

Solve 3x2 + 6x = 8.
1 plus or minus 2 square root 33
the quantity of negative 3 plus or minus I square root 15 all over 3
the quantity of negative 3 plus or minus square root 33 all over 3
1 plus or minus 2 i square root 15

Answer 1

Okay are these 5 different questions? It's really unclear.

Answer 2

For the first bit to solve 3x^2 + 6x = 8, have you heard of completing the square?

Answer 3

no the bottom ones are the answer choices

Answer 4

Oh right. So have you heard of completing the square?

Answer 5

no :/

Answer 6

It's a way to solve the trinomial like you have above. I'll show you the steps. \[3x^2+6x=8\] The first step is to move the constant (8) on the other side but that is already done. What you have to do now is to take half the coefficient of x and add it to both sides. Can you do that?

Answer 7

idk how.... man i must sound dumb as hell XD

Answer 8

@Sepeario

Answer 9

Nah this is actually pretty hard.. but very useful when you learn it. In the term 6x, what is the coefficient of x (the number before x essentially).

Answer 10

3?

Answer 11

the easiest thing to do is rewrite the equation as

\[3x^2 + 6x - 8 = 0\]

then use the general quadratic formula

for a quadratic \[ax^2 + bx - c = 0\]

the formula is

\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]

your question has a = 3, b - 6 and c = -8

substitute the values and calculate the answers

Answer 12

oops b = 6 a typo in the response above.

Answer 13

or you could do that.. I like completing the square. if you learn it it's much quicker than substituting values into the formula.

Answer 14

lol you still at this?

Answer 15

must be like a homework marathon

Answer 16

lol 51 questions XD @satellite73

Answer 17

i hope this is like 47 at least

Answer 18

what topic is this on?

Answer 19

do what @campbell_st said
use \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\] with \[a=3,b=6,c=-8\] that is all
compute carefully

Answer 20

probably quadratics and polynomials and stuff like that

Answer 21

i am i got \[-6\pm \sqrt{132}\6\]

Answer 22

want me to check it?

Answer 23

idk i just want the answer XD

Answer 24

im tired of algebra. its been 3 hours and im still on the same freaking thing!

Answer 25

that is the answer, before you "simplify it" it is probably not one of your answer choices

Answer 26

is one of them
\[\frac{-3\pm\sqrt{33}}{3}\]?

Answer 27

yes XD

Answer 28

then pick that one

Answer 29

how many more?

Answer 30

What is the simplified form of 3 over 2x minus 5 + 21 over 8 x squared minus 14x minus 15 ?
6 times the quantity 2 x plus 5 end quantity over the quantity 2x minus 5 end quantity times 4 x plus 3
6 times the quantity x plus 1 end quantity over the quantity 2x minus 5 end quantity times 4 x plus 3
6 time the quantity x plus 1 end quantity over the quantity 2x minus 5 end quantity times 4 x plus 3
6 times the quantity x plus 1 end quantity over the quantity 2x plus 5 end quantity times 4 x plus 3

Answer 31

yikes

Answer 32

those are just answer choices XD

Answer 33

and i think that it is 6 times the quantity x plus 1 end quantity over the quantity 2x minus 5 end quantity times 4 x plus 3

Answer 34

\[\frac{3}{2x-5}+\frac{21}{8x^2-14x-15}\] like that?

Answer 35

yes

Answer 36

i can't read your answer really
i know the denominator is correct
\[(2x-5)(4x+3)\]

Answer 37

6(x+1)/(2x-5)(4x+3)

Answer 38

What is the simplified form of the quantity 15 x y squared over x squared minus 5x plus 6 all over the quantity 5 x squared y over 2x squared minus 7x plus 3 ?
3y times the quantity 2x plus 1 over x times the quantity x plus 2
x times the quantity x plus 2 over 3y times the quantity 2x plus 1
x times the quantity x minus 2 over 3y times the quantity 2x minus 1
3y times the quantity 2x minus 1 over x times the quantity x minus 2

Answer 39

yikes

Answer 40

hard to read again let me try

Answer 41

XDDD

Answer 42

\[\frac{15xy^2}{x^2-5x+6}\]?

Answer 43

i need a screenshot maybe

Answer 44

idk how to do that

Answer 45

hit "print screen" on your keyboard, then attach it

Answer 46

it's not working...

Answer 47

ok give me a second
was any part of what i wrote correct?

Answer 48

i bet it was a compound fraction which amounts to \[\frac{15xy^2}{x^2-5x+6}\times \frac{2x^2-7x+3}{5x^2y}\]