Question

LAW OF SINES
Find B, C, and c.
A = 32°, a = 19, b = 14

Answer 1

I got B = 23°, C = 125°, c ≈ 29.4. Correct?

Answer 2

\[\huge \frac{ \sin32 }{ 19 }=\frac{ \sin B }{ 14 } \rightarrow sinB=\frac{ \sin32 }{ 19 } \times 14\]

Answer 3

\[\huge\ B=\sin^-1\left( \frac{ \sin32 }{ 19}\times14 \right)\]

Answer 4

\[\huge B= 22.98 \rightarrow B=23°\]

Answer 5

\[∠C=180-23-32 \rightarrow m∠C=125\]

Answer 6

\[\frac{ 19 }{ \sin 32 }=\frac{ c }{ \sin125 }\]\[c=\frac{ 19 }{ \sin32 } \times \sin125\]\[\huge c = 29.37°\]

Answer 7

Am I right?

Answer 8

You are correct, except that c is a side length so is not measured in degrees. Good job!

Answer 9

My bad. :D It was a side, not an angle. Thanks!