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Mathematics 18 Online
OpenStudy (anonymous):

For questions 3–4, what is the value of x to the nearest tenth? 3.) http://assets.openstudy.com/updates/attachments/5079d51ae4b02f109be49278-reno15-1350161710721-squaree.png my answer: 11.5. correct? 4.) http://assets.openstudy.com/updates/attachments/5079d51ae4b02f109be49278-reno15-1350161739880-second.png my answer: 3.6. Correct?

OpenStudy (anonymous):

lolly i can't help even if you asked me too cause u blocked meh

OpenStudy (anonymous):

I did??

OpenStudy (anonymous):

I HAVE NO idea why....I am very sorry

OpenStudy (anonymous):

oh u can still read this its okie then :P

OpenStudy (anonymous):

maybe I thought you were someone else?

OpenStudy (anonymous):

I really do not recall blocking you though, its freaking me out.

OpenStudy (anonymous):

4 is the 11.5 right?

OpenStudy (anonymous):

if so 4 is correct

OpenStudy (anonymous):

otherwise...both wrong

OpenStudy (anonymous):

neither of the answer has 3.6 in it

OpenStudy (anonymous):

well for number 4 apply pythagoras theorem 6.5^2 = 3^2 + y ^2 solve and get value of y which will be y = 5.76 as i have found the half of the length , so x =2y x =11.5

OpenStudy (anonymous):

ooh yah i messed up on 3 hold up

OpenStudy (anonymous):

yea lolli put on the 3) thats why i asked lol

OpenStudy (anonymous):

Hyp ^2 = base ^2 + perpendicular ^2 in your 3rd question case base = 11/2 perp = 3.6 so hyp^2 = 5.5^2 + 3.6^2 hyp^2 = 43.21 hyp =6.57 nah 3 is correct lol

OpenStudy (anonymous):

hopefully you are not lying

OpenStudy (anonymous):

me not

OpenStudy (anonymous):

i got 6.57

OpenStudy (anonymous):

two of us confirmed the answers :3 medal for doge

OpenStudy (anonymous):

it cant be 6.57 because that is not one of the options . Am I being played right now?

OpenStudy (anonymous):

nope wit r your choices?

OpenStudy (anonymous):

I'd rather not say so no one will just pick a random one and play me. I have been played before so.

OpenStudy (anonymous):

lemme draw it out for you|dw:1438681139344:dw|

OpenStudy (anonymous):

you can see it better now?

OpenStudy (anonymous):

exactly wit doge wrote

OpenStudy (anonymous):

it says round the nearest tenth so perhaps you didnt do that

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

can you post the answer choices? i will somehow figure it out and show meh steps

OpenStudy (anonymous):

I dont know why you are getting it wrong.

OpenStudy (anonymous):

but okay..

OpenStudy (anonymous):

._.

OpenStudy (anonymous):

the face is cute : O

OpenStudy (anonymous):

:P

OpenStudy (anonymous):

is one of the choices 6.6?

OpenStudy (welshfella):

r^2 = 3.6^2 + 5.5^2

OpenStudy (anonymous):

3.) 4.2 6.6 10.4 11.6 4.) 3.6 5.8 11.5 14.3

OpenStudy (anonymous):

yah its 6.6 6.57 rounds to 6.6

OpenStudy (welshfella):

the perpendicular line from the center to the chord bisects the chord

OpenStudy (anonymous):

did i do number 4 correctly?

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

lemee see

OpenStudy (anonymous):

did u get 11.5?

OpenStudy (anonymous):

3.6

OpenStudy (anonymous):

wrong

OpenStudy (anonymous):

then no cause i got 11.5

OpenStudy (anonymous):

lol i think i may have mixed up the asnwers

OpenStudy (anonymous):

i posted this above :P well for number 4 apply pythagoras theorem 6.5^2 = 3^2 + y ^2 solve and get value of y which will be y = 5.76 as i have found the half of the length , so x =2y x =11.5

OpenStudy (anonymous):

ah, I see. Well thank you guys for the corrections once again : 3

OpenStudy (anonymous):

np

OpenStudy (welshfella):

No. 4 6.5^2 = 3^2 + (0.5x)^2

OpenStudy (anonymous):

|dw:1438681557255:dw|Find the base of triangle and multiply by 2

OpenStudy (anonymous):

@welshfella is that correct then?

OpenStudy (welshfella):

yes

OpenStudy (anonymous):

alrighty

OpenStudy (welshfella):

11.5 is correct for number 4

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