For questions 3–4, what is the value of x to the nearest tenth?
3.) http://assets.openstudy.com/updates/attachments/5079d51ae4b02f109be49278-reno15-1350161710721-squaree.png
my answer: 11.5. correct?
4.) http://assets.openstudy.com/updates/attachments/5079d51ae4b02f109be49278-reno15-1350161739880-second.png
my answer: 3.6. Correct?
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OpenStudy (anonymous):
lolly i can't help even if you asked me too cause u blocked meh
OpenStudy (anonymous):
I did??
OpenStudy (anonymous):
I HAVE NO idea why....I am very sorry
OpenStudy (anonymous):
oh u can still read this its okie then :P
OpenStudy (anonymous):
maybe I thought you were someone else?
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OpenStudy (anonymous):
I really do not recall blocking you though, its freaking me out.
OpenStudy (anonymous):
4 is the 11.5 right?
OpenStudy (anonymous):
if so 4 is correct
OpenStudy (anonymous):
otherwise...both wrong
OpenStudy (anonymous):
neither of the answer has 3.6 in it
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OpenStudy (anonymous):
well for number 4 apply pythagoras theorem
6.5^2 = 3^2 + y ^2
solve and get value of y which will be y = 5.76
as i have found the half of the length , so
x =2y
x =11.5
OpenStudy (anonymous):
ooh yah i messed up on 3 hold up
OpenStudy (anonymous):
yea lolli put on the 3) thats why i asked lol
OpenStudy (anonymous):
Hyp ^2 = base ^2 + perpendicular ^2
in your 3rd question case
base = 11/2
perp = 3.6
so
hyp^2 = 5.5^2 + 3.6^2
hyp^2 = 43.21
hyp =6.57
nah 3 is correct lol
OpenStudy (anonymous):
hopefully you are not lying
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OpenStudy (anonymous):
me not
OpenStudy (anonymous):
i got 6.57
OpenStudy (anonymous):
two of us confirmed the answers :3
medal for doge
OpenStudy (anonymous):
it cant be 6.57 because that is not one of the options . Am I being played right now?
OpenStudy (anonymous):
nope wit r your choices?
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OpenStudy (anonymous):
I'd rather not say so no one will just pick a random one and play me. I have been played before so.
OpenStudy (anonymous):
lemme draw it out for you|dw:1438681139344:dw|
OpenStudy (anonymous):
you can see it better now?
OpenStudy (anonymous):
exactly wit doge wrote
OpenStudy (anonymous):
it says round the nearest tenth so perhaps you didnt do that
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
can you post the answer choices? i will somehow figure it out and show meh steps
OpenStudy (anonymous):
I dont know why you are getting it wrong.
OpenStudy (anonymous):
but okay..
OpenStudy (anonymous):
._.
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OpenStudy (anonymous):
the face is cute : O
OpenStudy (anonymous):
:P
OpenStudy (anonymous):
is one of the choices 6.6?
OpenStudy (welshfella):
r^2 = 3.6^2 + 5.5^2
OpenStudy (anonymous):
3.) 4.2
6.6
10.4
11.6
4.) 3.6
5.8
11.5
14.3
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OpenStudy (anonymous):
yah its 6.6 6.57 rounds to 6.6
OpenStudy (welshfella):
the perpendicular line from the center to the chord bisects the chord
OpenStudy (anonymous):
did i do number 4 correctly?
OpenStudy (anonymous):
yea
OpenStudy (anonymous):
lemee see
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OpenStudy (anonymous):
did u get 11.5?
OpenStudy (anonymous):
3.6
OpenStudy (anonymous):
wrong
OpenStudy (anonymous):
then no cause i got 11.5
OpenStudy (anonymous):
lol i think i may have mixed up the asnwers
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OpenStudy (anonymous):
i posted this above :P
well for number 4 apply pythagoras theorem
6.5^2 = 3^2 + y ^2
solve and get value of y which will be y = 5.76
as i have found the half of the length , so
x =2y
x =11.5
OpenStudy (anonymous):
ah, I see. Well thank you guys for the corrections once again : 3
OpenStudy (anonymous):
np
OpenStudy (welshfella):
No. 4
6.5^2 = 3^2 + (0.5x)^2
OpenStudy (anonymous):
|dw:1438681557255:dw|Find the base of triangle and multiply by 2
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