Question

grr

Answer 1

we know that your function has to be a polynomial of degree 2
from your drawing we see that x=6 and x=-6 are two zeroes of the requested polynomial

Answer 2

Oh! So would it be -1(x+6)(x-6) ??

Answer 3

the simpler polynomial which satisfies those requisites is:
\[y = \left( {x - 6} \right)\left( {x + 6} \right)\]
even if, we have to check if my function contains the point (0,36)
does my function pass at point (0,36)?

Answer 4

yes! that's right!

Answer 5

Ok so then I got -x^2+36?

Answer 6

correct!

Answer 7

There is a 2nd part to this question, I'm not getting

Answer 8

I know, I'm lost too:)

Answer 9

you have to create a table for a straight line like this one: