If h(x) = 5x − 3 and j(x) = −2x, solve h[j(2)] and select the correct answer below.

17
23
−17
−23

Question

If h(x) = 5x − 3 and j(x) = −2x, solve h[j(2)] and select the correct answer below.

 17
 23
 −17
 −23

danjs · Answer

For a compound function like that,, figure the innermost one out first, then use that value and move outwards

danjs · Answer

what is j(2) =     ?

help_people · Answer

to be honest i have no clue @DanJS

help_people · Answer

-4? or 4?

danjs · Answer

j(x) = -2x

j(2) = -2 * 2  =  -4

danjs · Answer

Now to calculate h[j(2)] ...

you use that value for j(2), for x in h

danjs · Answer

h( - 4) = ...

help_people · Answer

Yay! I got it right (Sort of) and how would you find h(-4)

help_people · Answer

^ @DanJS

danjs · Answer

if 
h(x) = 5x-3
then
h(-4) = 5*(-4) -3 
         =  -20 - 3   = -23

danjs · Answer

for those, work the inner function first, then keep using those output values and work outwards to the next function like we did

help_people · Answer

ok so am i done or i shtere more to go ?

help_people · Answer

@DanJS

danjs · Answer

that is it, you figured the inner function out, which was -4, then you use that value in the outer function  h(-4)   that is it

help_people · Answer

sp the answer is -23 ? @DanJS

help_people · Answer

*so

help_people · Answer

and if it is ty so much :) @DanJS

danjs · Answer

yes