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Given that f(x) = 2x + 1 and g(x) = the quantity of 3x minus 1, divided by 2, solve for g(f(3)). 5 7 9 10
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@Mehek14 would it be c?
Here's what you do
Substitute 3 for x in f(x) first
\(f(x)=2*3+1\)
multiply 2*3 first
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6+1 = 7
correct so now put 7 for x in g(x)
\(\dfrac{3*7-1}{2}\)
so 10 would be the answer ;)
yes :D
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you the besttt
tyyyy :D
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