Question

REALLY NEED HELP!!! :)
Line AB passes through A(-3, 0) and B(-6, 5). What is the equation of the line that passes through the origin and is parallel to line AB ?

Answer 1

5x – 3y = 0
-x + 3y = 0
-5x – 3y = 0
3x + 5y = 0
-3x + 5y = 0

Answer 2

I really have no clue how to do this :((((

Answer 3

HI!!

Answer 4

they are asking you for the slope of the line
or at least you need that first

Answer 5

Can you walk me through i'm completely lost

Answer 6

you know the slope of the line between (-3, 0) and (-6, 5) ?

Answer 7

if you do not, i can show you how to find it

Answer 8

yes please help me find it

Answer 9

first we think, then we do it the math teacher way

Answer 10

from -6 to -3 is right 3 units
from 5 to 0 is down 5 units
right 3, down 5, slope is \(-\frac{5}{3}\)

Answer 11

now the math teacher way
\[\frac{y_2-y_1}{x_2-x_1}=\frac{5-0}{-6-(-3)}=\frac{5}{-3}=-\frac{5}{3}\]

Answer 12

Okay so how is finding the slope going to give me the answer?

Answer 13

then since it goes through the origin \((0,0)\) the point slope formula gives
\[y=-\frac{5}{3}x\]

Answer 14

multiply by 3 to get
\[3y=-5x\]

Answer 15

add \(5x\) to both sides to put it in standard form get
\[5x+3y=0\]

Answer 16

oooooh okay :) Thank you!!!!

Answer 17

i see that is not an answer choice though

Answer 18

we can fix that
multiply all by -1 get
\[-5x-3y=0\]

Answer 19

oh wait its not :/

Answer 20

ohh alright thank you again much appreciated!

Answer 21

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