Question

when four dice are thrown (each numbered from 1 to 6), calculate the probability that all the numbers facing up are different .

where do i start??

Answer 1

interesting question.thanks for posting,,.needs an interpretation.

Answer 2

you start with the fact there are 4 dice

Answer 3

i was looking at all possible outcomes, 6*5*4*3*2*1=720 for each dice

Answer 4

understand where you are coming from, but I dont think that will provide a solution

Answer 5

okay,

Answer 6

consider the first dice. it has 6 possible alternatives.

Answer 7

Now, once the first possiblity is chosen there are 5 possible alternatives for the next 3 dice

Answer 8

Now you've got it!... So what is the overall probability?

Answer 9

0.277

thanks so much

Answer 10

it seems you multiplied the individual probabilites?

Answer 11

no wait... .

Answer 12

i multiplied it and got 1/360

Answer 13

but that doesnt sound right