when four dice are thrown (each numbered from 1 to 6), calculate the probability that all the numbers facing up are different .

where do i start??

Question

when four dice are thrown (each numbered from 1 to 6), calculate the probability that all the numbers facing up are different .

where do i start??

anonymous · Answer

interesting question.thanks for posting,,.needs an interpretation.

anonymous · Answer

you start with the fact there are 4 dice

marigirl · Answer

i was looking at all possible outcomes, 6*5*4*3*2*1=720 for each dice

anonymous · Answer

understand where you are coming from, but I dont think that will provide a solution

marigirl · Answer

okay,

anonymous · Answer

consider the first dice. it has 6 possible alternatives.

anonymous · Answer

Now, once the first possiblity is chosen there are 5 possible alternatives for the next 3 dice

marigirl · Answer

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anonymous · Answer

Now you've got it!... So what is the overall probability?

marigirl · Answer

0.277

thanks so much

anonymous · Answer

it seems you multiplied the individual probabilites?

marigirl · Answer

no wait... .

marigirl · Answer

i multiplied it and got 1/360

marigirl · Answer

but that doesnt sound right

anonymous · Answer

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