Question

Last question I need help on for tonight.

Answer 1

Part A: Which is the correct net for the prism? Explain your answer. (2 points)

Part B: Write the measurements of Sides AB, BC, and CD of the correct net. (4 points)

Part C: What is the surface area of the prism? Show your work. (4 points)

Answer 2

i believe net a is the correct net for the prism btw

Answer 3

yes, fold it up in your mind

Answer 4

Yes its net A

Answer 5

How would i go about doing part B?

Answer 6

yes, then write the corresponding measurements on it

Answer 7

like, AB is 3 in

Answer 8

CD = 9.4 in

BC you have to use pythagorean theorem to get

Answer 9

THe sides of that right triangle are 3 and 4, so the hypotenuse side is
root(3^2 + 4^2) = root 25 = 5

It is a 3-4-5 triangle

Answer 10

oh, the 5 is on the drawing, i missed it

Answer 11

so bc=5

Answer 12

yea

Answer 13

how do i find the area?

Answer 14

3*9.4*5*1/2?

Answer 15

total up the areas of every side...

Answer 16

3 rectangles and 2 triangles

Area Rectangle = Length x Width
Area Triangle = 0.5 x base x height

Answer 17

so 37.6 is the area of the rectangle and 15 is the area of the triangle

Answer 18

Rectangles:
9.4*4 + 9.4*5 + 9.4*3 = ..

Triangles:
0.5 * 4 * 3 + 0.5 * 4 * 3

Answer 19

add all those up for the total surface area

Answer 20

0.5 is 1/2 right?

Answer 21

yea

Answer 22

i got 112.8 and 6

Answer 23

so the total area is 118.8

Answer 24

yeah the area of 1 triangle is 6, but there are 2

Answer 25

add 6 more ,, and you are good

Answer 26

130.8

Answer 27

112.8 + 12 = 124.8 in^2 total surface area

Answer 28

oh yes i forgot to start from 112.8