Question

What are the exact solutions of x2 - 3x - 5 = 0?
x = the quantity of negative 3 plus or minus the square root of 29 all over 2 x = the quantity of 3 plus or minus the square root of 29 all over 2 x = the quantity of 3 plus or minus the square root of 11 all over 2 x = the quantity of negative 3 plus or minus the square root of 11 all over 2

Answer 1

@Mehek14

Answer 2

Since the given polynomial is not factorabl, we apply quadratic formula x = (-b ± √(b² - 4ac))/2a, along with ax² + bx + c = 0:

a = 1
b = -3
c = -5

x = (3 ± √((-3)² - 4*1*-5))/2
==> (3 ± √(9 + 20))/2
==> (3 ± √29)/2

Answer 3

Since the given polynomial is not factorabl, we apply quadratic formula x = (-b ± √(b² - 4ac))/2a, along with ax² + bx + c = 0:

a = 1
b = -3
c = -5

x = (3 ± √((-3)² - 4*1*-5))/2
==> (3 ± √(9 + 20))/2
==> (3 ± √29)/2

I hope this helps!