Question

let logba=3 logbc=2 logbd=5 what is the value of logb(A^5C^2/D^6) ?
1. 2
2. -15,378
3. -11
4. There isn't enough information to answer the question

Answer 1

\(\log_b(\frac{A^5C^2}{D^6})=\log_b(A^5C^2)-\log_b(D^6)=\log_b(A^5)+\log_b(C^2)-\log_b(D^6)\\=5\log_b(A)+2\log_B(C)-6\log_b(D)\)

Answer 2

So my answer would be 3?

Answer 3

how did you get that?

Answer 4

I plugged in 7 for the first log instead of 5. But I redid my calculations and got -11

Answer 5

Am I right ?

Answer 6

correct