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Mathematics 14 Online
OpenStudy (anonymous):

help please

OpenStudy (anonymous):

find the dual basis of {(1,0,0),(0,1,0),(0,0,1) and explain

OpenStudy (anonymous):

@zzr0ck3r

OpenStudy (anonymous):

@oldrin.bataku

OpenStudy (anonymous):

its a table

OpenStudy (anonymous):

please continue

OpenStudy (anonymous):

notice that the 1 shifts each time.

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

1, 0, 0 0,1,0 0,0,1 thats binary code

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

the first column is 2^0 second column is 2^1 third column is 2 ^2

OpenStudy (anonymous):

how?

OpenStudy (anonymous):

you know how to count in tens. you know the first column is 0-9 the second column is 10 - 19 etc., remember the abacus? it is similar for the binary system

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

I'll draw you a picture!

OpenStudy (anonymous):

|dw:1439037967941:dw|

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