How many grams of aluminum chloride must decompose to produce 78.3 milliliters of aluminum metal, if the density of aluminum is 2.70 g/mL? Show all steps of your calculation as well as the final answer.

I dont think I have the right answer. Can someone please check my work?

Question

How many grams of aluminum chloride must decompose to produce 78.3 milliliters of aluminum metal, if the density of aluminum is 2.70 g/mL? Show all steps of your calculation as well as the final answer. 

I dont think I have the right answer. Can someone please check my work?

anonymous · Answer

Show me your work ;)

rushwr · Answer

AlCl3(s)+6H2O(l)→[Al(H2O)6]3+(aq)+3Cl−(aq) This the reaction right? I'm not sure though ! But according to the question it says combustion. If AlCl3 is cumbusted it doesn't form Al metal right ?

rushwr · Answer

@Bozhena

anonymous · Answer

Actually in Water is should be like this:
AlCl3(s) + H2O(l) = Al(OH)3(s) + HCl(aq)

While for the combustion 
Im not sure, but whan you rise the T very higt it will break the bond between Al and Cl, and you should get Al(l).