Mathematics
8 Online
OpenStudy (anonymous):
find a_18 when a_1=27, d=-6
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OpenStudy (jhannybean):
Using an arithmetic sequence that follows the formula: \(a_n =a_1 +(n-1)d\)
OpenStudy (anonymous):
-75 is my answer
OpenStudy (jhannybean):
\[\large a_{\color{red}{n}} = a_{\color{red}{18}}\] Therefore we can conclude \(n=18\).
Let's see..
OpenStudy (jhannybean):
That is correct :)
OpenStudy (anonymous):
thank you, but i did it the long way, d=-6
a_1=27
a_n=?
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OpenStudy (jhannybean):
Perhaps you can show me how you've solved it?
OpenStudy (anonymous):
i did 27-6=21
21-6=15
15-6=9 and so on until i got to a18.
OpenStudy (anonymous):
but what is a_n?
OpenStudy (jhannybean):
That's also a good way to go about finding it.
OpenStudy (anonymous):
it cant be 27(18-1)-6.
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OpenStudy (jhannybean):
And why do you think it cant be?
OpenStudy (anonymous):
because i got 453
OpenStudy (anonymous):
and -2754 if i do the negative sign, first answer (453) i did a minus sign
OpenStudy (jhannybean):
This is how I solved it.\[a_n = a_{18} \longrightarrow n=18\]\[a_n=27+(18-1)(-6)\]\[a_n=27 -102\]\[a_n=-75\]
OpenStudy (anonymous):
thats why, i forgot the addition sign.
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OpenStudy (jhannybean):
:)
OpenStudy (anonymous):
thank you ma'am!
OpenStudy (jhannybean):
No problem and good luck!