f(x)=x^2+3x-4
find the domain,range, axis of symetry, and vertex
@Hero
@pooja195, help her
:)
Have you started this yet? If so what do you have so far? :)
No, I tried to but it didn't really make sense. I graphed it though by plugging in points
Thats fine Starting with all real numbers, the domain is the largest possible set of x values that has a meaningful y value. The largest possible set of x values is all the real numbers, since each real number has a meaningful output , there is no division by zero or square root of a negative number.
okay so the domain would be all real numbers?
yes :)
Wanna try out range?
sure
For range there is no simple formula. You have to look at the graph and find the y values which are 'hit'
y<=4?
Range would be the green line
if you shine a flashlight horizontally , the range is the shadow
so, y<-3/2??
thats the axis of symmetry
ok, so then what would the range be? Sorry, I dont understand this part
The range would be y>= -25/4 because the range is the y values of the ordered pairs of your function
oh okay! So now all we need is the vertex which is -1.5,-6.25?
Thats correct good job :)
Thanks for your help:))
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Lol! Aww! That's so sweet<3!!!! Thanks:D
:3 <3
ty you too, hero:)
@ChloeSiouz hold up theres a mistake
Ok:)
range is y>-4 it means you can't get value less than -4 by putting any value of x
Alright, is the axis of symmetry still the same though?
so, is everything else okay?
It remains the same. Everything else looks fine.
cool:)! Glad you caught that hhaaha:)
:)
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