Question

Again just checking my answer but don't know if it would be 16 or -16?

Answer 1

.

Answer 2

\(g(g(x)) = -(-x^2)^2 = -(x^2)^2 = -x^4\)

Answer 3

So, \(g(g(2))=...?\)

Answer 4

g o g (x) means put the g(x) function within itself
\[g(x) = -x^2 \]

\[(g o g) (x)= -(-x^2)^2\]
expanding that out gives
\[(g o g) (x)= -(-x^2)(-x^2)\]
while a negative times a negative is a positive, there is still a negative sign hanging outside
\[(g o g) (x)= -(x^4)\]
when we evaluate the function at x = 2
\[(g o g) (x)= -(2^4) = -16\]