Question

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Answer 1

binomial for this one
\[n=5,k=4,p=\frac{2}{3},1-p=\frac{1}{3}\]

Answer 2

there are 5 combinations of four days... do i just raise (2/3) to the fourth power?

Answer 3

use
\[P(x=4)=\binom{5}{4}\left(\frac{2}{3}\right)^4\left(\frac{1}{3}\right)\]

Answer 4

ohhhh i see

Answer 5

yeah 5 combinations of 4 days, and \(\frac{2}{3}\) gets raised to the power of 4,

Answer 6

but also one failure, so need the \(\frac{1}{3}\) there as well

Answer 7

got it. Thanks so much!

Answer 8

yw