Question

helpppppp

Answer 1

@jjamz87

Answer 2

ik its choice a and b but ineed the restriction?

Answer 3

\[\frac{x^2+4x-45}{x^2+10x+9}=\frac{x-5}{x+1}\]

Answer 4

The first step is to factor the numerator and denominator.

Answer 5

is the restriction -9

Answer 6

\[\mathrm{Factor}\:x^2+4x-45:\quad \left(x+9\right)\left(x-5\right)\]
\[=\frac{\left(x+9\right)\left(x-5\right)}{x^2+10x+9}\]
\[\mathrm{Factor}\:x^2+10x+9:\quad \left(x+9\right)\left(x+1\right)\]
\[=\frac{\left(x+9\right)\left(x-5\right)}{\left(x+9\right)\left(x+1\right)}\]
\[=\frac{\left(x+9\right)\left(x-5\right)}{\left(x+9\right)\left(x+1\right)}\]
\[\mathrm{Cancel\:the\:common\:factors:}\:x+9\]
\[=\frac{x-5}{x+1}\]
that is the answer

Answer 7

@jammy987 are you understand