Write an equation of a line perpendicular to y =1/4 x + 4 in slope-intercept form that passes through the point (-2, 6).
from the equation y=1/4 x +4 what is the slope of that line? (hint: In the form y=mx+b : m is the slope)
the slope is 1/4 so the new slope would be -4
im having trouble on how to find the b of the new equation
@MrNood do you know how to do that ?
ok so you have the new slope so the equation of th enew line would be y = -4x + b but you know that the point (-2,6) lies on the line so when x=-2 y= 6 so put those 2 numbers in the equation = and you will find b
okay so 6 = -4 * -2 + b 6 = 8 + b b = -2 Is that right @MrNood
check it by putting it back into the equation .... (it looks right to me...)
so the final answer would be y = -4 x - 2 right?
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