ennifer has been saving for college for 57 months. The first month, she saved $11. She was able to save more money each month than the month before. She ended up saving $19,779.00. How much more did she save each month?
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OpenStudy (anonymous):
@phi
OpenStudy (anonymous):
@peachpi
OpenStudy (anonymous):
What do you think? :)
OpenStudy (anonymous):
I'm thinking the final amount is the sum of an arithmetic series and they want you to find the common difference of the sequence
OpenStudy (anonymous):
I agree!
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OpenStudy (anonymous):
But I just dont know how to do it hahah
OpenStudy (anonymous):
Use this one to find \(a_{57}\), the amount saved in the 57th month.
\[S_{57}=\frac{ n }{ 2 }(a_1+a_{57})\]
n = 57 and \(a_1=11\)
OpenStudy (anonymous):
ok so s57=28.5(11+a57)
OpenStudy (anonymous):
Right and S_57 = 19779
OpenStudy (anonymous):
now what do we do?
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OpenStudy (anonymous):
solve for \(a_{57}\)
OpenStudy (anonymous):
What would I divide by?
OpenStudy (anonymous):
28.5
OpenStudy (anonymous):
694
OpenStudy (anonymous):
subtract 11
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OpenStudy (anonymous):
683
OpenStudy (anonymous):
that's the 57th term. This is the formula to find d\[a_n=a_1+d(n-1)\]
\[683=11+d(57-1)\]
OpenStudy (anonymous):
683=57d-d+11
OpenStudy (anonymous):
11.78=answer
OpenStudy (anonymous):
But the answer choices are
11.00
11.50
12.00
12.50
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OpenStudy (anonymous):
683=11 + 56d
OpenStudy (anonymous):
672 = 56d
OpenStudy (anonymous):
12:)
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Thanks :) If I open anothe question, will u answer it?