Question

Part A: The area of a square is (16x2 − 8x + 1) square units. Determine the length of each side of the square by factoring the area expression completely. Show your work.

Part B: The area of a rectangle is (81x2 − 4y2) square units. Determine the dimensions of the rectangle by factoring the area expression completely. Show your work.

Answer 1

Part A
By the identity
\[\Large (a ^{2} \pm 2ab+b ^{2})=(a \pm b)^{2}\]
\[\Large(16x^2 − 8x + 1)=(4x-1)^{2}\]
so the side of the square is 4x-1

Part B
By the identity
\[\Large(a ^{2} - b ^{2})=(a-b)(a+b)\]
\[\Large(81x^2 − 4y^2)=(9x-2y)(9x+2y)\]
then the sides of the rectangle are 9x-2y and 9x+2y

Answer 2

Does that help @SOAD_Fan ? :)

Answer 3

Ja :)

Answer 4

Awesome! Just wanted to make sure. @Natriumhydrid did a good job. :)

Answer 5

SOAD fan huh
what your fav album